Have a 19V ~ 4.74A notebook Li on battery gives data DC 11.1V (rating means as much as reception) right? 48Wh equals 4400mAh. My question is now I have a universal charger with 48watt from 9,5V-20V. At which volt do I set the charger. I'm a real greenhorn & don't want to let anything burn out
You won't have a charger but a power supply.
The power supply unit supplies your laptop with power, as the charge controller for the battery is also installed.
Socket → power supply → laptop → charge controller → battery
Your laptop probably has a 19V input (that should be on the laptop or you are looking at the original power supply), so you also set the power supply to 19V
Already not popped and loads
🤪Device embarrassed, thank you.
So you would like to have a new power supply for your notebook?
the actual charging electronics for the battery are located in the notebook, by the way, charging the battery outside of it is only possible with its own charging electronics.
So if it's really just the new power supply, the situation is relatively simple:
the new power supply has to deliver as much voltage as the original. When it is adjustable between 9.5 and 20 volts. So do NOT adjust itself! This is dangerous! Then the first step is the right one. Set to 19 volts!
in the second step it looks a bit gloomy again. The one you chose has 48 watts. 19 volts times 4.74 amps are much more. That's 90 watts.
So you need a power supply that delivers 19 volts and at least 4.74 amps (90 watts).
the 48 watt hours have nothing to do with that, they only tell you how much electricity is stored in the battery. Theoretically, with an average consumption of 48 watts of electricity for one hour, with a consumption of 24 watts of electricity for 2 hours, with a consumption of 96 watts, electricity for ½ hour…
