The title says it all, I want to run my MSI GS70 notebook with a power bank or can recharge.
The laptop itself has a hollow plug (size I know now not by heart ) and is supplied with an intermediate AC / DC converter, which in turn is connected by an IEC-C5 coupling to the mains.
If I now want to connect my power bank (which has only USB ports) with my laptop, then a USB is enough on hollow connector cable (with just the right pin size and a sufficient "power" of the cable? {But will, as the laptop is not possible}) or I have to buy a USB to IEC-C5 cable, if there's such a thing?
Or is the most sensible way to buy a USB to wall outlet adapter?
Or does not all work, because the power bank has too few watts, amperes or volts?
Maybe you would have to stop a transformer in between, if there are too few W.
Well, thank you for any answers.
and if your product links to cable or similar I would be very grateful to you.
Your power supply delivers according to the nameplate 19.5 V and 7.7 A.
And you want to replace that with a powerbank that delivers 5V and 2A.
Is so similar, as if you wanted to replace the engine in your car by a model car.
Can't go, you can't go synonymous.
Of that, I'm already strong, but it would not be possible with a DC / DC adapter to bring the 5V to 19.5V?
In addition, one would have to be able to transform the USB plug of the power bank to a socket output, even if that is of course associated with a very high loss.
Or am I wrong?
What is so "hard to understand" is so difficult to understand? You can "transform" electricity or voltage, but not performance. And that's not enough back and front.
I have to disappoint you. It will not work because your power bank is too weak. In addition, the tensions are too different. The power bank with 5V and 72Wh, compared to the laptop with 19.5V and 7.7A = 150 watts. Even if you made something, which does not justify the effort, theoretically only a maximum operating time of 15 minutes would be possible.
The statement does not make any sense, if you transform the voltage, but also increases the performance? P = U • I
Since no transformer would help the only shifts voltage and current in proportion. Ultimately, only counts the power in watts.
No, the performance remains the same (or is minimally lower due to losses)
Pzu 10W at 5V makes 2A… If you now transform the 5V to 10V, the performance remains the same (without any losses). You then have 10V, but only 1A… Since still converter losses are added, you have vlt still 0.7A, so only 7W output power…
A pity, thanks anyway.
Would this be possible, however, with a stronger power bank, which might produce a mains voltage of 230V possible? (Something like that ^^)
Ah, right, the amps will be halved. Naturally.
Physics is a bit too long, thank you.
Batteries of similar technology have the same size even with the same Wh. Electronics that regulate the voltage still cause losses.
Have a power bank, the 230V generated then have multiple losses because then even the charger comes to it.
It is possible but it will be unwieldy and difficult. As a battery you need at least a motorcycle battery and all around powerful electronics.